Abox of weight w=2.0n accelerates down a rough plane that is inclined at an angle ϕ=30∘ above the horizontal, as shown (figure 6). the normal force acting on the box has a magnitude n=1.7n, the coefficient of kinetic friction between the box and the plane is μk=0.30, and the displacement d⃗ of the box is 1.8 m down the inclined plane. what is the work ww done on the box by the weight of the box?

Explanation:

To calculate the work, we need to find all forces that are involved in the movement.

As you can analyse, the body is the force that make the box to move, and the friction force is opposite to it, we cannot forget about the friction. So, we have to calculate the resultant force to this context.

So, to find we use: ; where

The friction force would be:

Then, the resultant force is:

Now, we calculate the work:

Therefore, the work done is 0.882 Joules.

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle

did yall get answers for this yet