Answers: 3
![dB = 10Log[\frac{I}{I_o} ]\\\\170 = 10Log[\frac{I}{I_o} ]\\\\17 = Log[\frac{I}{I_o} ]\\\\10^{17} = \frac{I}{I_o}\\\\I = 10^{17} \times \ I_o\\\\I = 10^{17} \times \ 10^{-12} \ W/m^2\\\\I = 10^{5} \ W/m^2](/tpl/images/1004/1054/2dc2a.png)
![dB = 10Log[\frac{I_2}{I_o} ]\\\\dB = 10Log[\frac{160}{10^{-12}} ]\\\\dB = 142 \ dB](/tpl/images/1004/1054/24ba6.png)
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