A container is filled to a depth of 16.0 cm with water. On top of the water floats a 29.0-cm-thick layer of oil with specific gravity 0.500. What is the absolute pressure at the bottom of the container?

1.039×10^5pa

Explanation:

Pressure due to the weight of a liquid can be expressed as P= ρ g h ,

where p=pressure,

h=depth of the liquid

ρ = density of the liquid

g = acceleration due to gravity.

To calculate the the absolute pressure at the bottom of the container, we use below expresion

P(absolute)= P• [ρ(water) × h(water)× g] + [ ρ(oil) × h(oil)× g]

Where

P•= absolute pressure=101325 Pa

ρ(water= 1000 kg/m³

h(water)= 16.0 cm = 0.16m

ρ(oil)= 0.500= 500kg/m^3

h(oil)= 29.0-cm= 0.29m

If we substitute the values into the above expresion we have

P(absolute)=. 1.01×10^5 + (1000×0.16×9.8) + (500×0.28×9.8)

=1.039×10^5pa

Hence, the absolute pressure at the bottom of the container is 1.039×10^5pa

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