An antitank weapon fires a 3.00-kg rocket which acquires a speed of 50.0 m/s after traveling 90.0 cm down a launching tube. Assuming the rocket was accelerated uniformly, what is the average force acted on it?

~4166.67 N

Explanation:

We can find the acceleration that the rocket had by using one of the constant acceleration kinematics equations.

List out the motion variables we are given:

v_i = 0 m/sv_f = 50.0 m/sx = 90.0 cm → 0.9 m a = ?

Using the equation:

v_f² = v_i² + 2aΔx

We can plug in the known variables and solve for acceleration.

(50.0)² = (0)² + 2a(0.9)

Simplify this equation.

2500 = 1.8a

Divide both sides by 1.8.

a = 1388.88889 m/s²

Now we can use Newton's 2nd Law, F = ma, to determine the force acted on the rocket.

We know the mass of the rocket is 3.00-kg, and its acceleration is 1388.88889 m/s².

F = maF = (3.00)(1388.88889) F = 4166.66667 N

The average force acting on the rocket is about 4166.67 N.

Look it up you feel me

Amethod of procedure that has characterized natural science since the 17th century, consisting in systematic observation, measurement, and experiment, and the formulation, testing, and modification of hypotheses.