A cylindrical container is filled with oil to a depth of 32 cm if the pressure exerted at the base of the container is known to be. 2560pa then how much is the density if the oil?

The static pressure of the fluid can be calculated by the formula. The dencity of the given oil is 815 kg/m3.

The static pressure of the fluid can be calculated by the formula,  

P = Ro g h

Where,  

Ro = density [kg/m³] =?  

g = gravity acceleration = 9.81 m/s²  

h = depth = 32 cm = 0.32 m  

P = pressure = 2560 pa

put the values in the formula,  

2560 = Ro x 9.18 x 0.32

Ro = 815 kg/m3

Therefore, the dencity of the given oil is 815 kg/m3.

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Ro = 815 [kg/m³]

Explanation:

The static pressure of any fluid can be calculated by means of the following expression.

where:

Ro = density [kg/m³]

g = gravity acceleration = 9.81 [m/s²]

h = depth [m]

P = pressure [Pa]

Now we can calculate the depth

atomic = no of protons.

mass number-atomic number = neutron number

i dont know but

explanation:

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