1. A rocket is launched straight up into the air. If its entire flight takes 5 seconds A) What is the initial velocity of the rocket?
Om/s
B) What is the maximum height the rocket reaches?

1)49m/s

2)122.5m

Explanation:

The expression below can be use to calculate the initial velocity from law of motion

V2 - V1= at

Where V2= final velocity

V1= initial velocity( from rest)

a=acceleration

t= time= 5 seconds

But V2=0

V1=gt

Where g= acceleration due to gravity= 9.8m/s^2

V1= 9.8×5

V1=49m/s

Then we can now calculate the maximum height the rocket reaches by using below formula

V^2=2gh

h(max)=v^2/2g

Where h= maximum height

V2= initial velocity

=49^2/(2×9.8)

=2401/19.6

=122.5m

Hence the maximum height it reaches vis 122.5m

1/0.14nm = 10^10/1.4 a lot

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.