4 If a 50-kilogram student is pushed in a rolling chair with a force of 20 N, what is the student's
acceleration?
F. 2.5 m/s 2
G. 4.0 m/s 2
H. 1,000 m/s 2
J. 0.40 m/s2

i dont know but

explanation:

whoever your teacher is, deserves a raise for using pokemon as an example

connect the batteries in series and hope

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j