8. A hiker walks 2.3 km east and then 4.1 km north. What is her displacement? A. 6.4 km
B. 6.4 km at 45°
C. 4.7 km at 61°
D. 4.7 km at 29°

Firstly , draw the path 2.3 to east and 4.1 to the north. you’ll get a right - angle triangle . the hypotenuse is the displacement.

to find the distance , use Pythagoras theorem.

let the displacement = c

c ^ 2 = 2.3 ^ 2 + 4.1 ^ 2

c = 4.7 km

then , you need to find the angle.

tan theta = 4.1 / 2.3

theta = 61 degree

i am sorry if my answer was wrong but i hope it helps you and you can understand it : )