Rock A is thrown horizontally off of a cliff with a velocity of 20m/s. The rock lands 60m from the base of the cliff. According to the information and diagram above, what is the height of the cliff?

А. 10.1m

B. 44.1m

С. 60.0m

D. 210m

B. 44.1

Explanation:

We can use the equation y=1/2gt^2 to find the distance in the vertical direction, where y= distance in the vertical direction, g=acceleration due to gravity, and t=time

we only know acceleration due to gravity(9.8m/s^2),

plug in known variables,

y=1/2*9.8*t^2

we still need to plug in the time variable.

In order to do that, we an use the s=d/t equation and re arrange that formula to get: t=d/s, where t=time, d=distance, and s=speed.

plug in known variables,

t=60/20

t=3

now that we know the time, we can plug that into our original equation

y=1/2*9.8*3^2

simplify,

y=4.9*3^2

y=4.9*9

y=44.1m

Thus, B is your answer