A car jack works when a mechanic uses a force 3.8 N, on a small piston of radius 10 cm. What force can he exert on a larger piston of radius 0.22 m?

18.392 N

Explanation:

Given that,

Smaller force acting on the car, F₁ = 3.8 N

Radius of smaller radius, r₁ = 10 cm = 0.1 m

The radius of the larger piston, r₂ = 0.22 m

We need to find the force exerted on the larger piston. Let it is F₂.

Using the relation,

Hence, the force exerted on the larger piston is 18.392 N.

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