A perfect gas undergoes a constant 100 kPa pressure process with a 20 m3 change in volume. What is the work required to cause this volume change?

The work required to cause this volume change is 2 x 10⁶ J

Explanation:

Given;

constant pressure of the gas, P = 100 kPa = 100,000 Pa

change in volume of the gas, ΔV = 20 m³

The work required to cause this volume change is calculated as;

W = PΔV

Substitute the given values and solve for the required work (W).

W = (100,000)(20)

W = 2 x 10⁶ J

Therefore, the work required to cause this volume change is 2 x 10⁶ J