A 1.2-kg object moving at 5.0 m/s collides with and sticks to a 4.8-kg object initially at rest. What is the amount of kinetic energy lost by the system during this collision?

-15J

Explanation:

Step one:

given data

m1= 1.2kg

v1= 5 m/s

m2= 4.8kg

v2= 0 m/s

Required

The kinetic energy lost

Step two:

The kinetic energy before impact is KE1

KE after impact is KE2

The loss in Kinetic energy is

Loss in KE= KE2-KE1

Loss in KE= 0-15

Loss in KE= -15J

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

report!

explanation:

physics means: "the branch of science concerned with the nature and properties of matter and energy. the subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms."