A steel wire in a piano has a length of 0.540 m and a mass of 4.800 ✕ 10−3 kg. To what tension must this wire be stretched so that the fundamental vibration corresponds to middle C (fC = 261.6 Hz on the chromatic musical scale)?

T = 708.81 N

Explanation:

Given that,

Length of a steel wire in a piano, l =0.54 m

Mass,

We need to find the tension must this wire be stretched so that the fundamental vibration corresponds to middle C, fc = 261.6 Hz

The equation for fundamental frequency is given by :

So, the required tension in the wire is 708.81 N.

mistakes are ok

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