A physics student throws a ball thrown horizontally from the top of a building with a speed of 8 m/s. The student measures the height of the building to be 15m.

Following are the solution to the given question:

Explanation:

Please find the complete question in the attached file.

Distance:

Using the concept of motion, the answers to the question posed on the motion of a dropped ball are :

The vertical component of acceleration is denoted as :

The gravitational force acting on the ball in the downward direction has an acceleration of - 9.8 m/s². Hence,

Gravitational force only acts downwards along the vertical, hence, horizontal component of acceleration will be Zero.

then the vertical component of x, will be 0

The initial vertical velocity ; :

The time taken :

S = 0.5gt² ; S = distance = 15 meters ; g = - 9.81

15 = 0.5(9.8)t²

15 = 4.9t²

t² = (15 ÷ 4.9)

t² = 3.061

t = √3.061

t = 1.75 seconds

Landing Distance from building :

Horizontal speed × time taken

Therefore, the ball landed 14 meters away from the building.

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