A pitcher threw a baseball straight up at 35.8 meters per second. What was the ball's velocity after 2.50 seconds? (Note that, although the baseball is still climbing, gravity is accelerating it downward.)

The velocity after 2.5 seconds is 11.3 m/s

Explanation:

Given;

u = 35.8 m/s

t = 2.50s

g = 9.8 m/s^2

Mathematically;

V = U-gt

Substituting these values;

V = 35.8-2.5(9.8)

V = 35.8-24.5

V = 11.3 m/s

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14