Physics, 14.12.2020 01:00 ericahale3971

A 1220 kg automobile travels at 75 m/s. what net work would be required to bring it to a stop

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Answer from: lacourboud20005

W = - 3431250 [N]

Explanation:

In order to solve this problem, we must use the theorem of work and energy conservation. This theorem tells us that the initial mechanical energy of a body plus the work done on this body must be equal to the final mechanical energy of the body. We must remember that the mechanical energy of a body is equal to the sum of kinetic energies plus potential energy plus elastic energy.

In this problem, we only have kinetic energy.

$E_{1}+W_{1-2}=E_{2}\\where:\\E_{1}=E_{pot}+E_{kine}+E_{elas}\\E_{pot} = 0\\E_{elas}=0\\E_{kine}=\frac{1}{2} *m*v^{2}$

And we have:

m = mass = 1220 [kg]

v = velocity = 75 [m/s]

As the carriage stops the final kinetic energy is zero.

Now replacing:

$\frac{1}{2} *1220*(75)^{2} +W_{1-2}=0\\W_{1-2}= - 3431250[N]$

Note: The negative force means that the force has to be carried out by the carriage. That is, no external force acts on the car to stop it.

Answer from: Quest

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Answer from: Quest

Your answer is c. explanation: plasma is the fourth state of matter, derived from the gaseous state of matter. plasma can contain free electrons and/or ions. while plasma is never neutral, it can either be positively or negatively charged. gases, however, are electrically neutral.

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A 1220 kg automobile travels at 75 m/s. what net work would be required to bring it to a stop...

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