Solenoid 2 has twice the radius and six times the number of turns per unit length as solenoid 1. The ratio of the magnetic field in the interior of 2 to that in the interior of 1 is: 1/3 1 2 4 6

6

Explanation:

The magnetic field inside a solenoid is given by the following formula:

where,

B = Magnetic Field Inside Solenoid

μ₀ = permittivity of free space

n = No. of turns per unit length

I = Current Passing through Solenoid

For Solenoid 1:

For Solenoid 2:

n₂ = 6n₁

Therefore,

Diving equation 1 and equation 2:

Hence, the correct option is:

6

small = small current large mag large current

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