G volume of 0.025 m3. If the temperature of the gas is 290 K, what is the rms speed of the gas atoms

This question is incomplete, the complete question is;

Argon gas (a monatomic gas) is sometimes used to insulate a double-pane window for purposes of insulation. In a particular window, the space in between two glass sheets has a volume of 0.025 m³.

If the temperature of the gas is 290 K . what is the rms speed of the gas atoms ?

The atomic mass of Argon is 39.9 u.

(1 u = 1.66 x 10⁻²⁷ kg) Enter your answer in m/s.

Enter your Answer in m/s

the rms speed of the gas atoms is 425.754 m/s

Explanation:

Given that;

mass of Argon = 39.9 u

and 1 u = 1.66 x 10⁻²⁷ kg

so 39.9 × 1.66 x 10⁻²⁷ kg = 6.6234 x 10⁻²⁶

Temperature T = 290 K

Now

V_rms = √( 3KT / M)

where Boltzmann's constant K = 1.38 × 10⁻²³ m²kg s⁻² K⁻¹

so we substitute

V_rms = √( 3 × 1.38 × 10⁻²³ × 290 / 6.6234 x 10⁻²⁶)

V_rms = √( 181266.419)

V_rms = 425.754 m/s

Therefore the rms speed of the gas atoms is 425.754 m/s

i belive it is d. both a and c

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