How do I find net force when something has arrows all four directions with different N values for each? In the free-body diagram shown above, which of the following is the net force on the balloon?
1570 N
-570 N
1212 N
1070 N
Image shows arrows:
Pointing to right=950N
To left=1520N
up=5120N
down=4050N

In the vertical direction, take up to be positive and down to be negative. Then the net vertical force would be

5120 N - 4050 N = 1070 N

(it's positive, so the net vertical force is pointing upward)

In the horizontal direction, take right to be positive and left to be negative. Then the net horizontal force would be

950 N - 1520 N = -570 N

(negative means the net horizontal force points to the left)

So the net force on the balloon is the vector

F = (1070 N) i + (-570 N) j

(where i and j are the unit vectors in the horizontal and vertical directions, respectively)

The magnitude of the net force on the balloon is the magnitude of this vector:

F = √((1070 N)² + (-570 N)²)

F ≈ 1212 N

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

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