Physics, 09.12.2020 18:20 mikesleviticus08

A clown in a circus act swings a 2.7-kg metal ball attached to a 72.0-cm nylon string in a horizontal circle above her head, making one revolution in 0.98 s. What is the tension force, Ft, exerted on the string by the ball?

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Answer from: OperatorBravo

Tension, Ft = 79.91 N

Explanation:

The tension in the string is the resultant force that exists in the string due to the centripetal effect of the swinging ball.

From conservation laws, the tension in the string will be equals to the centripetal force acting on the string.

The tension in a string can be obtained using the formula:

T=mv^2/R

where v = linear velocity of the metal ball which equals to the angular velocity of the ball X the radius of the ball.

The radius of the ball is given as 72 cm = 0.72m and the angular velocity = 1.02 rad/second.

Therefore, linear velocity, $v = 2\pi \times 1.02\times 0.72 =4.616m/s$

The tension in the string will now be equals to $2.7 \times 4.616^2 /0.72 =79.91N$

Answer from: Quest

This is kenetic energy.

Answer from: Quest

m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| = √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| = √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| = 14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

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A clown in a circus act swings a 2.7-kg metal ball attached to a 72.0-cm nylon string in a horizonta...

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