The Roemer temperature scale sets the freezing point of water at 0.50 degrees Roemer and the boiling point at 60.0 degrees Roemer. What is the equivalent temperature in kelvins of 30.0 degrees Roemer

the equivalent temperature in kelvins of 30.0 degrees Roemer is 323 K

Explanation:

The computation of the equivalent temperature is as follows:

The freezing point of water is 0 degrees

As in the Roemer scale, o degrees means 0.5 degrees Roemer

Therefore

°C = ({Roemer} - 0.5 ) × 100 ÷ 59.5

As the boiling point is 100°C and the boiling point of 60.0 degrees would be obtained from the equation shown above

Now

If {° Roemer} = 30°

{°C} = (30 - 0.5) × 100 ÷ 59.5

= 49.57°C

So,

= 49.57°C  + 273 K

= 322.57  K

= 323 K

Hence, the equivalent temperature in kelvins of 30.0 degrees Roemer is 323 K

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.

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