A natural gas pipeline with a diameter 0.250 m delivers 1.55 cubic meters of gas per second. What is the flow speed of the gas in the pipeline?

The flow speed of the gas in the pipeline is 31.57 m/s.

Explanation:

Given;

diameter of the pipeline, d = 0.25 m

radius of the pipeline, r = d/2 = 0.125 m

volumetric flow rate of the gas, Q = 1.55 m³/s

The cross sectional area of the pipeline is given as;

A = πr²

A = π(0.125²)

A = 0.0491 m²

Volumetric flow rate is given by;

Q = Av

Where;

v is the speed of the fluid in the pipeline

v = Q / A

Therefore, the flow speed of the gas in the pipeline is 31.57 m/s.

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s