A stone is thrown horizontally from the top of a cliff with an initial speed of 15 m/s. A stopwatch measures the stone’s trajectory time from the top of the cliff to the bottom at 7.4 s. What is the height of the cliff? 36.3 m
16 m
111m
268 m

The height of the cliff is 90.60 meters

Explanation:

It is given that,

Initial horizontal speed of the stone, u = 10 m/s

Initial vertical speed of the stone, u' = 0 (as there is no motion in vertical direction)

The time taken by the stone from the top of the cliff to the bottom to be 4.3 s, t = 4.3 s

Let h is the height of the cliff. Using the second equation of motion in vertical direction to find it. It is given by :

h = 90.60 meters

So, the height of the cliff is 90.60 meters. Hence, this is the required solution.

hope this helps

i guess it’s a and b

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm