A2.0 kg block on an incline at a 60.0 degree angle is held in equilibrium by a horizontal force, what is the magnitude of this horizontal force (disregard friction)?

Horizontal force is 16.97 N.

Explanation:

It is given that,

Mass of the block, m = 2 kg

It is on an incline at a 60 degree angle is held in equilibrium by a horizontal force. We need to find the magnitude of horizontal force. The force acting on the block is its weight mg.

The horizontal component of force is,

The vertical component of force is,  

So, the horizontal component of force is,

So, the horizontal component of force is 16.97 N.

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