a 2.75 kg box is pushed across the floor with a force of 15 N. it experiences a frictional force of 8 N. calculate the acceleration of the box

Acceleration is 2.55m/s²

Explanation:

Force(F)=mass of object(m) ×acceleration(a)

in the scenario above,a force of 15N is used to push the box and because the floor is not having a smooth surface,frictional force(8N) will oppose the 15N used to push the box thereby decreasing the acceleration. so the actual force moving the box is 7N.

Force =Normal Force - Frictional Force

F= 15N - 8N

F= 7N

therefore the 7N is the actual force causing the box to move.

To find the acceleration,insert the mass of the box and the actual force into the formula (F=m×a)

F=m×a

7N =2.75kg × a

make a the subject by dividing both sides of the equation by 2.75kg.

7/2.75 = (2.75×a)/2.75

a= 7/2.75

therefore a= 2.55m/s²,where a is the Acceleration.

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle