The components of vectors A and B are given as follows: Ax = 7.6

Bx = -5.1

Ay = -9.2

By = -6.8

What is the magnitude of the vector difference B - À?

|B - A| = 12.92 units

Explanation:

In order to find the magnitude of B-A vector, we first write A and B in Vector Notation:

A = Aₓ i + Ay j

A = 7.6 i - 9.2 j

B = Bₓ i + By j

B = -5.1 i - 6.8 j

So, there difference will be:

B - A = (-5.1 i - 6.8 j) - (7.6 i - 9.2 j)

B - A = -12.7 i + 2.4 j

Now, the magnitude of this vector can be found out by using the formula:

|B - A| = √[(x-component)² + (y-component)²]

|B - A| = √[(-12.7)² + (2.4)²]

|B - A| = 12.92 units

the answer is 100. i just did this lesson and got a 100% on it. : )

-fishtank