Question 6 (14 points) A 3.68 kg object is tied to the end of a cord and whirled in a horizontal circle of radius 881 cm. The object completes 10.8 revolutions every 18.8
s. What is the centripetal acceleration of the object?

Explanation:

Given that,

Mass of an object, m = 3.68 kg

It is whirled in a horizontal circle of radius 881 cm or 8.81 m

The object completes 10.8 revolutions every 18.8 s.

We need to find the centripetal acceleration of the object. It is given by the formula as follows :

...(1)

Where is angular velocity

10.8 revolutions = 67.85 rad

Put values in equation (1)

So, the centripetal acceleration of the object is .

v 154.9= 0.9 length length s little over 154.9cm

the motion of a pendulum is a classic example of mechanical energy conservation. a pendulum consists of a mass (known as a bob ) attached by a string to a pivot point. as the pendulum moves it sweeps out a circular arc, moving back and forth in a periodic fashion.