Rodney hits a 0.060 kg tennis ball straight up with a speed of 15 m/s from a height of 2.2 m above the ground. How fast is the ball going when it is 9.5 m above the ground?

Explanation:

From the question we are told that

   The mass of the tennis ball is  

    The speed is  

    The initial height of the ball is  

     The height considered is  

Generally the time taken to reach the considered height is mathematically evaluated from the equation of motion as follows

=>        

=>        

=>          

solving the above equation using quadratic formula

            and  

Generally from kinematic equation we have that

=>    

=>      

Note if we had used the second values of time the velocity at 9.5 \ m would have been negative which is not correct given that at maximum height velocity is zero

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.