A block wełghing 300 N is moved at a constant speed over a horizontal surface by a force of 50 N. What is the coefficient of friction? *
1 point
A. 0.25
OB. 0.50
C. 0.10
D. 0.17

D) miu = 0.17

Explanation:

To be able to solve this problem we must perform a sum of forces in the direction of the movement. This sum of forces must be equal to zero, since the block moves at a constant speed, therefore there is no acceleration.

The friction force is defined as the product of the normal force by the coefficient of friction.

where:

f = friction force = 50 [N]

miu = friction coefficient

N = normal force [N]

Now the normal force is defined as the force with equal magnitude to the weight of the block but acting in the opposite direction.

Now replacing:

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.