A fish is 4.7 cm from the front surface of a fish bowl of radius 21 cm. Where does the fish appear to be to someone in air viewing it from in front of the bowl? Do not forget the proper sign. (Give your answer in cm.) cm

Where does the fish appear to be when it is 38.9 cm from the front surface of the bowl? (Give your answer in cm.)

cm

Explanation:

From the information given:

We can properly determine the distance where the fish appear in the air viewing it from in front of the bowl by using the formula:

where;

= refractive index in the air;  = 1.33  &

= refractive index in water. = 1

= - 3.74 cm

2)

To determine where the fish appear to be when it is  38.9 cm from the front surface of the bowl by using the formula:

-54.12  cm

this one:

as we gain mass the force of gravity on us increases.

pls mark me as the ! : d

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.