A large ball of Play-Doh with a mass of 0.04kg is launched from a catapult with an initial speed of 5m/s and an
initial height of 1.0m. What is the final speed of the ball right before it strikes the ground? Draw a picture!

  ≈ 6.68 m/s

Explanation:

A suitable formula is ...

  vf^2 -vi^2 = 2ad

where vi and vf are the initial and final velocities, a is the acceleration, and d is the distance covered.

We note that if the initial launch direction is upward, the velocity of the ball when it comes back to its initial position is the same speed, but in the downward direction. Hence the problem is no different than if the ball were initially launched downward.

Then ...

  vf = √(2ad +vi^2) = √(2·9.8 m/s^2·1.0 m+(5 m/s)^2) = √44.6 m/s

  vf ≈ 6.68 m/s

The ball hits the ground with a speed of about 6.68 meters per second.

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We assume the launch direction is either up or down.

answer: i'm not sure which is which for i get confused on it all the time but i can tell you that the answer lies with the convex and concave devices. i hope this you. have a good day and best of luck to you!

explanation:

false

hope this : d