I 5. An electric field has a strength of 10.0 N/C at a distance of 1.00 m from an unknown charge. At
what distance from the charge does the electric field strength equal 2.50 N/C?

The electric field strength is equal to 2.50 newtons per coulomb at a distance of 2 meters.

Explanation:

From Classic Electrostatic Theory, we find that electric field (), measured in newtons per coulomb, is defined by the following equation:

(1)

Where:

- Electrostatic force, measured in newtons.

- Electric charge, measured in coulombs.

In addition and supposing that phenomena occurs between particles, electrostatic force is modelled after the Coulomb's Law:

(2)

Where:

- Electromagnetic constant, measured in newton-square meters per square coulomb.

, - Electric charges, measured in coulomb.

- Distance between particles, measured in meters.

By applying (2) in (1), we get the following definition of electric field:

(3)

Then, we observe that electric field is inversely proportional to the square of the distance. The following relationship is therefore constructed:

(4)

If we know that , and , then the distance is:

The electric field strength is equal to 2.50 newtons per coulomb at a distance of 2 meters.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards