How much heat is needed to raise the temperature of an empty 2.0 x 101 kg vat made of iron from 10.0ºC to 90.0ºC?

Q = 7272 Kilojoules.

Explanation:

Given the following data;

Mass = 2.0*101kg = 202kg

Initial temperature, T1 = 10°C

Final temperature, T2 = 90°C

We know that the specific heat capacity of iron = 450J/kg°C

*To find the quantity of heat*

Heat capacity is given by the formula;

Where;

dt = T2 - T1

dt = 90 - 10

dt = 80°C

Substituting the values into the equation, we have;

Q = 7272KJ or 7272000 Joules.

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