A skateboarder skates down a ramp for 3 seconds. If his initial velocity was 0.8 m/s and · his final velocity was 7 m/s, what was his acceleration?

The acceleration of the skateboarder is 2.067 m/s²

Explanation:

Given;

initial velocity of the  skateboarder, u = 0.8 m/s

final velocity of the  skateboarder, v = 7 m/s

time of motion, t = 3 s

The acceleration of the skateboarder is given as;

Therefore, the acceleration of the skateboarder is 2.067 m/s²

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer