Physics, 29.11.2020 09:00 Janderson6422
A 1kg cannon ball. is fired horizontally with an initial velocity of 5m/s. If the cannon was atop a wall 20m above the ground, what is the total change in KE?
Answers: 2
![E_{1}=E_{2}\\E_{k1}+E_{p1}=E_{k2}\\\frac{1}{2} *m*v^{2} +m*g*h=E_{k2}\\E_{k2}=0.5*1*(5)^{2} +1*9.81*20\\E_{k2}=208.7[J]](/tpl/images/0932/2123/8cc4c.png)
![E_{k1}=\frac{1}{2} *m*v^{2}\\E_{k1}=0.5*1*(5)^{2}\\E_{k1}=12.5 [J]](/tpl/images/0932/2123/59349.png)
![E_{k} = 208.7 - 12.5\\E_{k} = 196.2 [J]](/tpl/images/0932/2123/36460.png)
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A 1kg cannon ball. is fired horizontally with an initial velocity of 5m/s. If the cannon was atop a...
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