When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth. If the muscle generates a force of 39.5 N39.5 N and it is acting with an effective lever arm of 2.75 cm2.75 cm, what is the torque that the muscle produces on the wrist?

Explanation:

Torque is expressed according to the formula;

Torque = Force × radius

Given

Force = 39.5N

Radius = 2.75cm

Convert radius to metres

100cm ,= 1m

2.75cm = (2.75/100)

2.75cm = 0.0275m

Find the torque

Torque = 39.5×0.0275

Torque = 1.08625Nm

Hence the torque is 1.08625Nm

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

trig 15.3 cos