A bus is moving with a velocity of lom/s. After 2 sec its velocity
becames 20/s find the distance from travelled
by a bus at that this time of interval

30 m

Explanation:

We are given:

Initial velocity (u) = 10 m/s

Final velocity (v) = 20 m/s

Time interval (t) = 2 seconds

Distance travelled by the bus (s) = s meters

Solving for the distance travelled:

Solving for the acceleration:

v = u + at                                                            [first equation of motion]

20 = 10 + a(2)                                                    [replacing the given values]

2a = 10                                                               [subtracting 10 from both sides]

a = 5 m/s²                                                         [dividing both sides by 2]

Solving for the distance:

s = ut + 1/2 (at²)                                                  [second equation of motion]

s = 10(2) + 1/2(5)(2)²                                           [replacing the given values]

s = 20 + 10

s = 30 m

Therefore, the bus travelled 30 m in the given time interval

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000

inverse v=i*r

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