and 
, respectively.
(1)
- Vector momentum, measured in kilogram-meters per second.
- Mass of the particle, measured in kilograms.
- Vector velocity, measured in meters per second.
and ![\vec v = 2.98\,\hat{i}-3.98\,\hat{j}\,\,\,\left[\frac{m}{s} \right]](/tpl/images/0926/1080/b1898.png)
, then the momentum is:![\vec p = (2.93)\cdot (2.98\,\hat{i}-3.98\,\hat{j})\,\,\,\left[\frac{kg\cdot m}{s} \right]](/tpl/images/0926/1080/520d5.png)
![\vec p = 8.731\,\hat{i}-11.661\,\hat{j}\,\,\,\left[\frac{kg\cdot m}{s} \right]](/tpl/images/0926/1080/e2039.png)
(2) 
(3)
- Magnitude of momentum, measured in kilogram-meters per second. 
- Direction of momentum, measured in sexagesimal degrees.
and 
, then the magnitude and direction of momentum are, respectively:
A 2.93 kg particle has a velocity of (2.98 i hat - 3.98 j) m/s.
Required:
a. Find its x and y...
Physics, 24.11.2020 18:20 tremainewoodley3030
A 2.93 kg particle has a velocity of (2.98 i hat - 3.98 j) m/s.
Required:
a. Find its x and y components of momentum.
b. Find the magnitude and direction of its momentum.
Answers: 3
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