2.05 × 108 kg of water is pumped up through a vertical height of 500 m.

1 x 10¹²J

Explanation:

Given parameters:

Mass of the water pumped  = 2.05 x 10⁸kg

Height  = 500m

Unknown:

Potential energy = ?

Solution:

The potential energy amassed by water at this height is expressed as;

           P.E  = mgH

m is the mass

g is the acceleration due to gravity

H is the height

        Insert the parameters and solve;

     P.E  = 2.05 x 10⁸ x 9.8 x 500 = 1 x 10¹²J

no sign of dia of fuel cell

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2