A rope of negligible mass supports a block that weighs 30.0 N. as shown below. The maximum tension the rope can support without breaking is 50.0 N. What is the maximum acceleration the weight can be pulled upwards with without breaking the rope? (Use g = 10 m/s)
WON

The maximum acceleration will be "6.7 m/s²".

Given:

By applying the formula,

→

or,

→                            

By substituting the values, we get

→                          

→                              

→                                

→                                

Thus the above answer is right.

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a = 6.7 m/s²

Explanation:

The formula to apply here is :

Mass * acceleration = Tension -weight

m*a = Ft -mg  where m is mass of block, a is acceleration , Ft  is force due to tension.

Given in the question that ;

Mass of block = 3 kg

Ft = 50 N

g= 10

m*a = Ft -mg

3*a = 50-30

3a= 20

a= 20/3

a= 6.7 m/s²

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .