A pelican flying along a horizontal path drops a fish from a height of 4 m. The fish travels 8.0 m horizontally before it hits the water below. What is the pelican’s speed Pls solve to the fullest do not copy question and give very detail of how to do it pls and thank you

Speed = 8.79m/s

Explanation:

Given the following data;

Height = 4m

Horizontal distance = 8m

To find the time, we would use the second equation of motion

S = ut + ½at²

We know that acceleration due to gravity is equal to 9.8m/s²

Initial velocity, u = 0

Substituting into the equation, we have;

4 = 0(t) + ½*9.8*t²

4 = 0 + 4.9*t²

4 = 4.9t²

t² = 4/4.9

t² = 0.82

Taking the square root of both sides, we have;

t = 0.91 secs

To find the speed;

Speed = horizontal distance/time

Speed = 8/0.91

Speed = 8.79m/s

Therefore, the pelican's speed is 8.79 meters per seconds.