A spring is 17 cm long when it is lying on a table. One end is then attached to a hook and the other end is pulled by a force that increases to 25 N, causing the spring to stretch to a length of 19.2 cm. How much work was required to stretch the spring? A. 3.13 J
B. 0.552 J
C. 1.67 J
D. 0.276 J

im pretty sure it B but I recommend waiting for another person. I used the workdone formula (Force*Dictance*cos(theta) and got 55 Joules

Explanation:

D. 0.276 J

Explanation:

When I solved this, I got 0.275, so I chose the one closest.

To solve:

convert 17 cm and 19.2 cm to 0.17 m and 0.192 m

W(on spring) = 1/2 (0.192 m - 0.17 m)(25N)

                     = 1/2 (.022 m)(25 N)

                     = 0.275