The charge of a capacitor is 1500μC. Determine the potential difference between the plates if their capacitance is 5μF.

The potential difference between the plates of the capacitor is 300V

Explanation:

Given;

capacitance of the capacitor, C = 5μF = 5 x 10⁻⁶ F

charge of the capacitor, Q = 1500μC = 1500 x 10⁻⁶ C

The potential difference between the plates of the capacitor is given by;

V = Q / C

Where;

V is the  potential difference between the plates

Q is the charge of the capacitor

C is the capacitance

Therefore, the potential difference between the plates of the capacitor is 300V

i would like to make dinner for my mom, dad, and sister

volts times amps 6 x 0.5 3w