An airplane accelerates with a constant rate of 3.0 m/s2 starting at a velocity of 21 m/s. If the final velocity is 60 m/s,

what is the displacement during this period?

526.5m

Explanation:

Given parameters:

Acceleration = 3m/s²

Initial velocity  = 21m/s

Final velocity  = 60m/s

Unknown:

Displacement = ?

Solution:

To solve this problem, we apply the right motion equation which is shown below;

     V²  = U²  + 2aS

  V is the final velocity

  U is the initial velocity

  a is the acceleration

 S is the displacement

 Insert the parameters and solve;

    60²  = 21² + 2(3)S

    3600 = 441 + 6S

    3600 - 441  = 6S

    3159  = 6S

       S = 526.5m

found in the nucleus

has mass of one amu