A beach ball, moving with a velocity of 2 m/s, rolls off a pier and hits the water 0.5 m from the end of the pier. It strikes the water 0.25 seconds later. How high is the pier above the water? Disregard air resistance. 1.23 m 0.31 m 0.61 m 2.45 m

0.31 m

Explanation:

The following data were obtained from the question:

Horizontal distance (s) = 0.5 m

Horizontal velocity (u) = 2 m/s

Time (t) = 0.25 s

Height (h) of the pier =.?

The height of the pier can be obtained as illustrated below:

Time (t) = 0.25 s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) of the pier =.?

h = ½gt²

h = ½ × 9.8 × 0.25²

h = 4.9 × 0.0625

h = 0.31 m

The, the height of the pier is 0.31 m

i already answered it by 34/s

find the sum of the two horizontal vectors and the sum of the two vertical vectors

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