What is the magnitude of the angular momentum (in kgm2/s) of a 40 g golf ball flying through the air and spinning at 4300 rpm after having been hit? The golf ball can be modelled as a uniformly dense sphere with a radius of 2.5 cm.

Explanation:

Given that,

The mass of a golf ball, m = 40 g = 0.04 kg

Its angular velocity,

The radius of the sphere is 2.5 cm or 0.025 m

We need to find the magnitude of the angular momentum of the ball. It is given by the formula as follows:

Where I is moment of inertia

For sphere,

So, the magnitude of the angular momentum of the sphere is .

i believe the answer is a hope it and is correct