A spring compresses 0.8 m when the 800 kg crate of llamas slides down and hits it. Ignore friction and find the spring constant of the spring. The ramp is at a 47° angle.

7167.27N/m

Explanation:

To get the force constant k, we will use the formula;

F = kx where

F is the force acting on the object down the plane

k is the spring constant

x is the extension

The force acting down the ramp us F = Wsintheta. The formula will become;

Wsintheta = kx

mgsintheta = kx

K = mgsintheta/x

K = (800)(9.8)sin47°/0.8

K= 7840sin47°/0.8

K = 5733.81/0.8

K = 7167.27N/m

Hence the spring constant of the spring is 7167.27N/m

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards