A 3kg ball is swung on the end of a 1m long string that is twirled with a speed of 3.2 m/s. What is the centripetal acceleration acting on the ball?

The centripetal acceleration acting on the ball is 10.24 m/s²

Explanation:

Given;

mass of the ball, m = 3 kg

radius of the swing arm, r = 1 m

speed of the ball, v = 3.2 m/s

centripetal acceleration is given by;

a = v² / r

a = (3.2)² / 1

a = 10.24 m/s²

Therefore, the centripetal acceleration acting on the ball is 10.24 m/s²

50 inches should be the resultant vector