An 18 000-kg freight car travelling 1.75 m/s[E] collides with a 27 000-kg freight car at rest. After the collision, the freight cars stick together. What is the velocity of the freight cars after the collision?

The velocity of the freight cars after collision is 0.7 m/s

Explanation:

Given;

mass of the first freight car, m₁ = 18000 kg

initial speed of the first freight car, u₁ = 1.75 m/s

mass of the second freight car, m₂ = 27000 kg

initial speed of the second freight car, u₂ = 0

Let the velocity of the freight cars after collision = v

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

18000(1.75) + 27000(0) = v(18000 + 27000)

31500 = 45000v

v = 31500 / 45000

v = 0.7 m/s

Therefore, the velocity of the freight cars after collision is 0.7 m/s

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

-reverse card

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.