A 5000 kg open train car is rolling on frictionless rails at 22 m/s when it starts pouring rain. A few minutes later, the car’s speed is 20 m/s. What mass of water has collected in the car?

The mass of the  water collected in the car due to the rain is 500 kg.

The given parameters;

The mass of water collected in the car is determined by applying the principle of conservation of linear momentum as shown below;

Thus, the mass of the  water collected in the car due to the rain is 500 kg.

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500 kg

Explanation:

It is given that,

The mass of a open train car, M = 5000 kg

Speed of open train car, V = 22 m/s

A few minutes later, the car’s speed is 20 m/s

We need to find the mass of water collected in the car. It is based on the conservation of momentum as follows :

initial momentum = final momentum

Let m is final mass

MV=mv

Water collected = After mass of train - before mass of train

= 5500 - 5000

= 500 kg

So, 500 kg of water has collected in the car.

if the thermos has a vacuum innner, then heat through conv currents and conduction are reduced = vacuum flask

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6